KEVOS® MAKEOS · Maintenance

Bearing Fleet Spares Plan (Rating Life, Weibull Failures, Spares for a Service Level)

For a group of identical bearings in service, how many are expected to fail over the planning period, and how many spares must I hold to be this sure of not running out?

Spares plan for identical rolling bearings: the basic rating life L₁₀ from the dynamic rating, equivalent load and speed (as the bearing life tool), the Weibull characteristic life that puts 10 % of failures at L₁₀ for the slope you enter, the probability that one bearing fails within the planning period (as the Weibull reliability tool), the expected number of failures in the group, and the smallest number of spares whose binomial probability of covering all failures reaches your service level, against the spares held.

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How this tool works

Inputs, units and where to find them

InputUnitTypical source
Bearing typechoiceBall or roller bearing (sets the life exponent).
Basic dynamic load ratingkNBasic dynamic load rating from the bearing maker’s catalogue.
Equivalent dynamic loadkNEquivalent dynamic load on each bearing in service.
SpeedrpmRunning speed of each bearing.
Weibull slope of bearing lifeWeibull slope of bearing life scatter; the reliability factor a₁ in the bearing selection check corresponds to a slope of 1.5. Use your own failure records where you have them.
Fleet and plan
Identical bearings in servicebearingsNumber of identical bearings running under the same load and speed.
Running hours per yearh/yearRunning hours of each bearing per year.
Planning periodyearsPeriod the spares must cover (often the resupply time or a stock-review period).
Chance of not running out%Probability that the spares cover every failure in the period.
Spares heldbearingsSpares in stock now.

What each input means

Open an input to see what it is, its units, the worked example and the common mistakes, with a small diagram.

What this means: Bearing type
Illustration: Bearing typeThe options for Bearing type, with the one currently selected highlighted.Ball bearing (exponent 3)Roller bearing (exponent 10/3)Example: Ball bearing (exponent 3)Bearing type
What it is
Whether the bearings are ball or roller bearings, which sets the life exponent in the rating life formula: 3 for ball and ten-thirds for roller bearings.
Units and format
Choose one of 2 options from the list: Ball bearing (exponent 3); Roller bearing (exponent 10/3).
Example
The form opens with “Ball bearing (exponent 3)” selected as a worked example. Choose the option that matches your case.
Effect on the result
The roller exponent makes life more sensitive to the load ratio.
Get it right
Tapered, cylindrical and spherical roller bearings all use the roller exponent.
What this means: Basic dynamic load rating
Illustration: Basic dynamic load ratingA block with an arrow pushing on it; the arrow is the force Basic dynamic load rating.CExample: 30 kNBasic dynamic load rating
What it is
The basic dynamic load rating of the bearing from the maker’s catalogue: the load at which 90 % of a group of bearings reach one million revolutions.
Units and format
Enter a number in kN: kilonewtons (1 kN = 1000 N). The form accepts 0.000001 kN to 100000 kN. Required: the tool does not calculate until every input is valid.
Example
The form opens with 30 kN as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
Life rises with the cube (ball) of the rating, so fewer bearings fail and fewer spares are needed.
Get it right
Use the rating for the exact bearing designation and maker; ratings differ between makers.
What this means: Equivalent dynamic load
Illustration: Equivalent dynamic loadA block with an arrow pushing on it; the arrow is the force Equivalent dynamic load.PExample: 3 kNEquivalent dynamic load
What it is
The constant radial load that would give the same life as the actual combination of radial and axial loads on each bearing in service.
Units and format
Enter a number in kN: kilonewtons (1 kN = 1000 N). The form accepts 0.000001 kN to 100000 kN. Required: the tool does not calculate until every input is valid.
Example
The form opens with 3 kN as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
Life falls with the cube (ball) of the load, so failures and spares rise sharply.
Get it right
Work it out from the loads with the maker’s X and Y factors (the bearing selection check does this).
What this means: Speed
Illustration: SpeedA turning disc with a marker; Speed is how many full turns it makes in each minute.turns of the shaftper minutenExample: 1450 rpmSpeed
What it is
The rotational speed of each bearing in service, which turns the rating life in revolutions into running hours.
Units and format
Enter a number in rpm: revolutions per minute. The form accepts 0.000001 rpm to 1000000 rpm. Required: the tool does not calculate until every input is valid.
Example
The form opens with 1450 rpm as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
A higher speed shortens the life in hours, so more bearings fail in the period.
Get it right
Use the shaft speed of the bearing itself, after any belt or gear ratio.
What this means: Weibull slope of bearing life
Illustration: Weibull slope of bearing lifeTwo bars: a base value and the same value multiplied by Weibull slope of bearing life, the factor.base valuewith factorβExample: 1.5Weibull slope of bearing life
What it is
The Weibull shape parameter describing how widely the lives of identical bearings scatter; it fixes how the 10 % failure point at the rating life spreads into failures over time.
Units and format
Enter a plain number with no unit. The form accepts 0.3 to 10. Required: the tool does not calculate until every input is valid.
Example
The form opens with 1.5 as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
With running time well below the rating life, a steeper slope predicts fewer early failures.
Get it right
Use your own failure records where you have them; the reliability factor in the bearing selection check corresponds to 1.5.

Fleet and plan

What this means: Identical bearings in service
Illustration: Identical bearings in serviceA row of identical items being counted; Identical bearings in service is how many there are.NExample: 40 bearingsIdentical bearings in service
What it is
The number of identical bearings running under the same load and speed that the spares must cover, such as the same bearing on a row of pumps or conveyor idlers.
Units and format
Enter a number in bearings: bearings. The form accepts 1 bearings to 1000 bearings. Use a whole number. Required: the tool does not calculate until every input is valid.
Example
The form opens with 40 bearings as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
Expected failures and the spares needed rise with the number in service.
Get it right
Group only bearings with similar duty; bearings on different loads need separate plans.
What this means: Running hours per year
Illustration: Running hours per yearA timeline from a start mark to an end mark; Running hours per year is the time between them.startendtExample: 4000 h/yearRunning hours per year
What it is
The running hours of each bearing per year, which with the planning period gives the running time over which failures are counted.
Units and format
Enter a number in h/year: h/year. The form accepts 0.000001 h/year to 8784 h/year. Required: the tool does not calculate until every input is valid.
Example
The form opens with 4000 h/year as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
More hours raise the chance of failure per bearing and the spares needed.
Get it right
Count only hours turning; a machine on one shift runs about 2000 hours a year.
What this means: Planning period
Illustration: Planning periodA timeline from a start mark to an end mark; Planning period is the time between them.startendtExample: 1 yearsPlanning period
What it is
The length of time the spares must cover, such as the resupply time for an imported bearing or the period between stock reviews.
Units and format
Enter a number in years: years. The form accepts 0.01 years to 50 years. Required: the tool does not calculate until every input is valid.
Example
The form opens with 1 years as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
A longer period raises the chance of failure per bearing and the spares needed.
Get it right
For a long-lead bearing use at least the resupply time; fractions of a year are accepted.
What this means: Chance of not running out
Illustration: Chance of not running outA bar of 100 parts with the share marked; Chance of not running out is that share out of 100. The bar follows the value you type.0 %100 %Example: 95%Chance of not running out
What it is
The probability that the spares held will cover every bearing failure in the period, the service level the stock is sized to.
Units and format
Enter a number in %: percent: the number is read as a percentage, so type 8 for 8 %. The form accepts 50% to 99.99%. Required: the tool does not calculate until every input is valid.
Example
The form opens with 95% as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
A higher service level raises the spares needed.
Get it right
Critical bearings whose failure stops production justify a high level; the spares needed grow quickly near 100 %.
What this means: Spares held
Illustration: Spares heldA row of identical items being counted; Spares held is how many there are.nExample: 3 bearingsSpares held
What it is
The number of these bearings in the store now, compared with the number needed and used to find the chance that they cover all failures.
Units and format
Enter a number in bearings: bearings. The form accepts 0 bearings to 1000 bearings. Use a whole number. Required: the tool does not calculate until every input is valid.
Example
The form opens with 3 bearings as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
Only moves the pass or fail line and the cover reported; the failures expected do not change.
Get it right
Count only bearings in good condition, correctly stored and in date for their grease.

Method and formulas

  1. L₁₀ = (C ÷ P)^p × 10⁶ ÷ (60 n) hours, p = 3 for ball and 10/3 for roller bearings (as the bearing life tool).
  2. Characteristic life η = L₁₀ ÷ [ln (1 ÷ 0.9)]^(1/β); chance one bearing fails in t hours F = 1 − exp[−(t ÷ η)^β] (as the Weibull reliability tool).
  3. Failures in the group follow a binomial distribution with N bearings and probability F; spares needed = smallest s with P(X ≤ s) ≥ the service level.
  4. Example: L₁₀ is 11,494 h; each bearing has a 2.1397 % chance of failing, 0.85589 failures are expected and 3 spares give 95 % cover.

Limitations

  • All bearings start the period as new and a replaced bearing is not counted failing again; with a high chance of failure per bearing, renewals add more demand.
  • Rating-life model only: lubrication, contamination, misalignment and installation damage often decide real bearing life.
  • Example values are illustrations. Replace them with values for your actual task.

Typical uses

  • Set stock levels for critical bearings
  • Check whether a store holds enough spares for a fleet of pumps or conveyors
  • Show how load and speed drive spares demand

Who it is for

  • Maintenance planners
  • Reliability engineers
  • Stores and purchasing staff

What you get

  • L₁₀ life and Weibull characteristic life
  • Chance of failure per bearing and expected failures
  • Spares needed for the service level against spares held

Interpreting the result

  • Life varies with the cube of the load ratio for ball bearings, so a small overload multiplies the spares a fleet needs.

References

  • Machinery’s Handbook, 29th edition (Industrial Press, 2012), printed pp. 2403–2415, 128–133. Topic reference; no source tables or recommended settings are reproduced.
  • NIST/SEMATECH e-Handbook of Statistical Methods, 1.3.6.6.18 Binomial Distribution — https://www.itl.nist.gov/div898/handbook/eda/section3/eda366i.htm

Learn the Concepts Behind This Tool

These KEVOS® Library readings explain the method this tool uses, with worked examples.

KEVOS® tools are screening and decision-support utilities. Verify important financial, engineering, safety, legal or operational decisions using appropriate professional standards and your organisation’s approved data.

Open the Bearing Fleet Spares Plan (Rating Life, Weibull Failures, Spares for a Service Level) calculator