Chapter 10 of 11 · 10 min read
Estimating cycle time
Build a cycle-time estimate operation by operation, add non-cutting time and handling, check it against simulation and actual results, and find where the time really goes.
A quote, a schedule and a capacity plan all depend on one number: how long the part takes. Getting it wrong in either direction is expensive. Too high, and the quote loses the work. Too low, and the job runs at a loss while the schedule slips.
The previous chapters calculated cutting times feature by feature. This chapter assembles them into a full estimate for the Harbourline flange, adds the time when the machine is running but not cutting and the time spent loading and unloading, and shows how to check and improve the estimate.
The parts of a cycle
The time a part spends on a machine has several components:
- Cutting time: the tool is engaged and removing material, calculated from length and feed rate as in Chapters 3 to 5.
- Non-cutting machine time: the machine is running the program but not cutting. Rapid moves between features, approach and retract moves, tool changes or turret indexing, spindle acceleration and deceleration, dwell, coolant start and in-process probing all belong here.
- Load and unload: the operator or a loading device removes the finished part, cleans the fixture or chuck, loads the next blank and starts the cycle. If loading is done while the machine runs, for example with a pallet changer, it may not add to the cycle at all.
- Per-part allowances: periodic tasks spread over the batch, such as in-process inspection, chip clearing and tool changes at the end of tool life.
Set-up, programming and first-article inspection happen once per batch or once per job. They are not part of the cycle time, but they are part of the cost, and Chapter 11 treats them separately.
Cutting time for the flange
Using the cutting data from earlier chapters, Harbourline’s estimator lists every cut on each operation. The values come from the formulas already shown: turning time from length, feed and spindle speed; facing time with constant surface speed; and drilling, tapping and milling times from feed length and feed rate.
| Operation | Cut | Cutting time (min) |
|---|---|---|
| 10, lathe | Face Ø110 to centre | 0.223 |
| 10 | Indexable drill Ø38 through | 0.265 |
| 10 | Rough turn Ø110 to Ø100.5, two passes | 0.289 |
| 10 | Finish turn Ø100 | 0.201 |
| 10 | Finish bore Ø40 | 0.188 |
| 20, lathe | Face to length, Ø110 to Ø38 | 0.190 |
| 20 | Rough spigot Ø110 to Ø60.5, ten passes | 0.584 |
| 20 | Finish spigot Ø60 and flange back face | 0.194 |
| 30, machining centre | Drill 6 × Ø11 | 0.324 |
| 30 | Drill 2 × Ø6.8 | 0.078 |
| 30 | Tap 2 × M8 | 0.129 |
| 30 | Face mill flat | 0.128 |
| Total | 2.79 |
Operation 10 accounts for 1.17 minutes of cutting, operation 20 for 0.97 and operation 30 for 0.66.
The spigot roughing time of 0.584 minutes is consistent with the removal-rate check in Chapter 3: about 66.8 cm³ removed at around 136 cm³/min is roughly half a minute of pure cutting, plus the approach length on each of the ten passes.
Non-cutting machine time
Non-cutting time is harder to calculate by hand and is best taken from a CAM simulation or from similar programs that have already run. Harbourline estimates:
| Operation | Main non-cutting items | Estimate (min) |
|---|---|---|
| 10 | Five tool indexes, approach and retract for each cut, spindle speed changes, rapid moves | 1.6 |
| 20 | Four tool indexes, approach and retract including ten roughing passes, rapid moves | 1.2 |
| 30 | Four tool changes, probing the part datum, rapid moves between ten holes, spindle reversal for tapping | 1.4 |
Adding these to the cutting times gives the machine cycle time for each operation: 2.77 minutes for operation 10, 2.17 for operation 20 and 2.06 for operation 30, a total of 6.99 minutes.
Load, unload and handling
The operator must remove each finished part, blow chips from the chuck or fixture, load the next blank and press cycle start. For this part, Harbourline estimates 0.6 minutes per part on each lathe operation and 0.8 minutes on the machining centre, where the part must be located on a fixture with the bore and a datum face. That adds 2.0 minutes.
The estimated machine time per part, including handling, is therefore 8.99 minutes, or about 9 minutes.
Spreading tool changes and checks over the batch
Some work happens only every so often, but it still belongs in the time per part. Tool changes at the end of an edge’s life are the main example. This is an illustration with assumed figures for four of the flange’s tools:
| Tool | Parts per edge | Time to change | Allowance per part (min) |
|---|---|---|---|
| Roughing insert | 60 | 2 min | 0.033 |
| Finishing insert | 120 | 2 min | 0.017 |
| Boring insert | 40 | 2 min | 0.050 |
| Ø11 carbide drill | 300 | 1.5 min | 0.005 |
| Total | 0.105 |
About a tenth of a minute per part looks small against a nine-minute cycle, but it is real machine time, and it grows quickly when tool life is short. Chapter 8 showed how a modest increase in cutting speed can halve tool life; the allowance per part then doubles as well, which partly offsets the time the faster speed was meant to save.
In-process checks are treated the same way. If the operator measures the bore and spigot on every tenth part, and each check takes about a minute with the machine waiting, that adds 0.1 minutes per part. Where checks can be done while the next part cuts, they cost operator attention but not machine time, and the estimate should say which applies.
Harbourline adds these allowances as a separate line rather than inflating the cycle time. That keeps the measured cycle comparable with the estimate, and it shows clearly where a change in tool life or inspection frequency would affect the job.
Where the time goes
| Component | Time per part (min) | Share |
|---|---|---|
| Cutting | 2.79 | 31% |
| Non-cutting machine time | 4.20 | 47% |
| Load and unload | 2.00 | 22% |
| Total | 8.99 | 100% |
Less than a third of the time is spent cutting. That is typical of small parts with many features and several set-ups, and it changes where improvement effort should go. Raising every cutting speed by 10% would save only about 0.25 minutes per part and shorten tool life considerably. Halving the non-cutting time through better programming, fewer tools and shorter approach distances would save about two minutes.
- Cutting
- Non-cutting machine time
- Load and unload
Practical ways to reduce non-cutting and handling time include:
- Fewer tools. Combination tools, such as a drill that also chamfers, remove tool changes.
- Optimised rapids and approach distances. CAM defaults are often generous.
- Multiple parts per fixture. On operation 30, a fixture holding four flanges would share each tool change and probing cycle across four parts.
- Fewer operations. A lathe with live tooling could drill, tap and mill the flange in operation 20, eliminating operation 30’s set-up and handling entirely, though at a higher machine rate and with more complex programming.
- Faster loading. Quick-change jaws, pneumatic fixtures and blanks ready at the machine.
- Overlapped loading. Pallet changers or a second station let the operator load while the machine cuts.
- Do: Fewer toolscombination tools remove tool changes
- Do: Tighter rapids and approachesCAM defaults are often generous
- Do: Several parts per fixtureshare tool changes and probing on operation 30
- Do: Fewer operationslive tooling could absorb operation 30
- Do: Faster and overlapped loadingquick-change jaws, pallets, blanks ready
- Avoid: Raising every cutting speedsmall saving, much shorter tool life
Checking the estimate
Estimates should be checked against reality as soon as possible:
- CAM simulation gives good cutting and rapid times but often underestimates real cycle time because it ignores acceleration, tool change mechanics and control processing.
- Prove-out of the first part gives an actual cycle time, but the first part often runs more slowly than production, with feed overrides turned down and extra stops for checking.
- Production records from the control’s cycle timer, over a full batch, give the most reliable figure.
Harbourline records the estimated and actual cycle times for every new job and reviews the difference. Over time, that record provides correction factors for its own machines, operators and programming style, and makes the next estimate better.
A quick estimate before the details
Not every enquiry justifies a full feature-by-feature estimate. For a first answer, a shop can estimate from similar parts it has already made: list the main features, compare them with a part whose actual cycle time is known, and adjust for the differences in material removed, hole count and number of operations. The record of estimated and actual cycle times described below is what makes this reliable.
A quick estimate should be labelled as such, with a range rather than a single figure, and replaced by a detailed estimate before a firm price is given. The worst outcome is a quick estimate that becomes a firm quote by default, because nobody went back to check it.
From cycle time to capacity
For scheduling, cycle time is not the same as the hours a batch occupies a machine. Machines stop for breaks, minor problems, waiting for material and shift changes. Overall equipment effectiveness, which combines availability, performance and quality, describes the gap between ideal and actual output. A machine with 75% effectiveness running a 2.77-minute cycle produces fewer than the theoretical 21.7 parts per hour.
There are two common approaches to that gap. One is to build the losses into the hourly rate, so the rate covers an hour of paid time that includes some unproductive minutes, and estimate at ideal cycle time. The other is to use a rate per productive hour and add an allowance to the cycle time. Either works if it is applied consistently. Harbourline uses the first approach, so its quotes use the cycle estimate directly.
From cycle time to batch time
For the order of 120 flanges, the total machine time across all three operations is:
120 × 8.99 ≈ 1,079 minutes, or about 18 hours
That figure is the basis for cost. Lead time is different. If the three operations run one after another, the batch occupies the shop for about 18 hours of machine time plus three set-ups. If the operations run at the same time on their three machines, with parts passing from one to the next in small transfer batches, the batch moves at the pace of the slowest operation: operation 10, at about 3.37 minutes including handling, gives about 120 × 3.37 ≈ 404 minutes, or 6.7 hours, plus the time for the first parts to reach the last operation.
| Operations in sequence | Operations overlapped | |
|---|---|---|
| Machine time | About 18 hours | About 18 hours |
| Time the batch takes | About 18 hours plus set-ups | About 6.7 hours plus start-up |
| What sets the pace | Every operation in turn | The slowest operation, Op 10 |
Neither figure includes set-up, waiting or the losses described below. They answer different questions: cost per part comes from total machine time, and a promised delivery date comes from the flow of the batch through the shop.
Balancing the operations
The three operations run on different machines. If the same operator tends both lathes and the machining centre, the longest operation sets the pace of the batch and the operator’s time is shared among them. Including handling, operation 10 takes about 3.37 minutes, operation 20 about 2.77 and operation 30 about 2.86. If the operations run at the same time, the batch moves at the pace of operation 10. Moving the face-to-length cut or some roughing from operation 10 to operation 20 would balance the line. That affects lead time and capacity, even though the total machine time and cost per part stay the same.
Common mistakes
- Estimating cutting time only. For small parts it can be under a third of the total.
- Trusting CAM times uncritically.
- Forgetting handling and per-part allowances.
- Mixing productive-hour and paid-hour approaches between estimate and rate.
- Never comparing estimate with actual.
Questions to ask
- What share of the cycle is cutting time, and where is the rest going?
- Which non-cutting items could be removed or shortened?
- Is the hourly rate built on paid hours or productive hours, and is the estimate consistent with it?
- How did the last similar job’s actual cycle time compare with its estimate?
Exercise: break down a real cycle
Take a part currently in production. Using the program and the control’s cycle timer, split the cycle into cutting, non-cutting and handling time. Identify the three largest non-cutting items and estimate the saving from reducing each.
The final chapter turns the cycle time into a quotation, adding material, set-up, programming, tooling and the effect of batch size.