KEVOS® MAKEOS · Materials

Electric Tank Heater Sizing (Heat-up, Losses and Watt Density)

How much heater power will bring this tank up to temperature in time, and is the installed heater’s surface loading safe for the liquid?

Sizing of an electric immersion heater for a tank: energy to heat the liquid and the vessel (as the heating energy tool), average surface loss during heat-up and holding loss at temperature from an overall loss coefficient, the power needed for the heat-up time with a margin, the heat-up time with the installed heater, holding duty and the element surface watt density against your limit for the liquid.

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How this tool works

Inputs, units and where to find them

InputUnitTypical source
Tank and liquid
Liquid volumeLVolume of liquid heated.
Liquid densitykg/m³Density of the liquid.
Liquid specific heatkJ/kg·KSpecific heat of the liquid (4.18 water, about 1.9–2.1 oils).
Vessel mass heatedkgMass of tank steel that heats up with the liquid.
Vessel specific heatkJ/kg·KSpecific heat of the vessel material (about 0.5 steel).
Starting temperature°CTemperature at the start of heat-up.
Set temperature°CWorking temperature.
Ambient temperature°CSurrounding air temperature.
Tank surface area losing heatm²Outside area of walls, bottom and liquid surface that lose heat.
Overall loss coefficientW/m²·KOverall loss coefficient (about 1–2 insulated, 5–10 bare steel in still air; an open liquid surface loses far more).
Heat-up time wantedhTime allowed to reach the set temperature.
Power margin%Margin on the power found.
Heater
Installed heater powerkWRated power of the heater fitted or considered.
Number of elementsNumber of heater elements.
Heated surface per elementcm²Heated (sheath) surface of one element.
Largest watt density for the liquidW/cm²Highest surface watt density the liquid accepts (your value from the heater maker; much lower for oils and viscous liquids than for water).

Method and formulas

  1. Heat-up energy Q = (m c + m_v c_v)(T_s − T₀), with m = V ρ.
  2. Loss during heat-up ≈ U A [(T₀ + T_s) ÷ 2 − T_amb]; holding loss = U A (T_s − T_amb).
  3. Power needed = (Q ÷ t + heat-up loss) × (1 + margin); heat-up time with the installed heater = Q ÷ (P − heat-up loss).
  4. Watt density = installed power ÷ (elements × heated surface per element).
  5. Example: heating 1000 L from 15 to 60 °C in 3 h needs 19.848 kW; the 21 kW heater does it in 2.5734 h.

Limitations

  • Uniform liquid temperature; poorly stirred tanks stratify.
  • Evaporation from an open hot surface can dominate the losses and is not included in a simple U value.
  • Example values are illustrations. Replace them with values for your actual task.

Typical uses

  • Size a heater for a wash, plating or oil tank
  • Check an existing heater’s heat-up time
  • Check watt density so oil or solutions do not burn on the elements

Who it is for

  • Plant engineers
  • Maintenance engineers
  • Process engineers

What you get

  • Heat-up energy and losses
  • Power needed and actual heat-up time
  • Holding duty and watt density

Interpreting the result

  • If the holding duty is very low, a smaller heater with a longer heat-up time may be acceptable.

References

  • Machinery’s Handbook, 29th edition (Industrial Press, 2012), printed pp. 371–378. Topic reference; no source tables or recommended settings are reproduced.

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Open the Electric Tank Heater Sizing (Heat-up, Losses and Watt Density) calculator