KEVOS® MAKEOS · Materials

Heating Energy and Time

How much energy and time does it take to heat this material or liquid?

Energy to raise a mass through a temperature range from its specific heat, and the heating time with a given heater power and efficiency.

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How this tool works

Inputs, units and where to find them

InputUnitTypical source
Mass to heatkgMass of the material or liquid (water: 1 kg per litre).
Specific heat capacitykJ/(kg·K)Specific heat over the range (water about 4.18, steel about 0.49, aluminium about 0.90 kJ/kg·K).
Start temperature°CStarting temperature.
Final temperature°CTarget temperature.
Heater powerkWRated heater power.
Heating efficiency (heat reaching the load)%Share of heater output that reaches the load (losses to surroundings reduce it).
Energy priceAUD/kWhEnergy tariff for cost per batch.

Method and formulas

  1. Q = m c (T₂ − T₁) (kJ); in kWh ÷ 3600.
  2. Time = Q ÷ (P × η) (hours when Q is in kWh).
  3. Energy drawn = Q ÷ η; cost = energy drawn × price.
  4. Example: 500 kg of water from 15 to 60 °C needs 26.125 kWh, about 3.415 h with 9 kW.

Limitations

  • No phase change (melting or boiling) is included; add latent heat separately.
  • Heat loss during heating is represented only by the efficiency.
  • Example values are illustrations. Replace them with values for your actual task.

Typical uses

  • Size a tank or oven heater
  • Estimate warm-up time
  • Compare energy cost of heating batches

Who it is for

  • Process engineers
  • Maintenance engineers

What you get

  • Heat energy required
  • Heating time
  • Energy drawn and cost per batch

Interpreting the result

  • Heat losses rise with temperature; use a lower efficiency for long, hot warm-ups.

References

  • Machinery’s Handbook, 29th edition (Industrial Press, 2012), printed pp. 371–374. Topic reference; no source tables or recommended settings are reproduced.

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