KEVOS® MAKEOS · Strength

Rectangular Bar in Torsion

What shear stress and twist does torque cause in this rectangular or square bar?

Maximum shear stress, angle of twist and torsional constant of a solid rectangular bar under torque, using Roark’s approximations.

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How this tool works

Inputs, units and where to find them

InputUnitTypical source
TorqueN·mTorque transmitted.
Long sidemmLonger side of the section.
Short sidemmShorter side (equal to b for a square).
LengthmmLength over which twist is wanted.
Shear modulusGPaShear modulus (steel about 79 GPa, aluminium about 26 GPa).
Allowable shear stressMPaAllowable shear stress from your design code.

Method and formulas

  1. τmax ≈ T(3b + 1.8c) ÷ (b² c²).
  2. K = b c³ [1/3 − 0.21 (c/b)(1 − c⁴ ÷ 12b⁴)].
  3. Twist θ = T L ÷ (K G).
  4. Example: 200 N·m on a 40 × 20 mm bar gives τmax = 48.75 MPa and 0.98649° of twist over 500 mm.

Limitations

  • Approximate formulas (within a few per cent); stress concentrations at re-entrant corners are not included.
  • The bar ends are assumed able to warp.
  • Example values are illustrations. Replace them with values for your actual task.

Typical uses

  • Check square drive shafts and flat bars in torsion
  • Compare a flat bar with a round shaft
  • Estimate twist of a torsion arm

Who it is for

  • Design engineers
  • Structural and mechanical engineers
  • Engineering students

What you get

  • Maximum shear stress (mid-point of the long side)
  • Torsional constant K
  • Angle of twist

Interpreting the result

  • A rectangular section is much less stiff in torsion than a round or closed tube of the same area.

References

  • Machinery’s Handbook, 29th edition (Industrial Press, 2012), printed pp. 295–303. Topic reference; no source tables or recommended settings are reproduced.

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Open the Rectangular Bar in Torsion calculator