Boolean Constructions and Discriminator Varieties
Ultraproducts and Jonsson's Lemma
Jónsson's lemma is the sharpest tool in the subject. Under congruence distributivity it locates every subdirectly irreducible member of a generated variety inside HS of ultraproducts of the generators.
- Construct the ultraproduct of a family of algebras.
- State Jónsson's lemma with its hypotheses.
- Explain why congruence distributivity is essential.
- Derive the finite case where ultraproducts collapse.
- List the structural consequences for finitely generated CD varieties.
- Recognise where the lemma fails without distributivity.
01The ultraproduct construction
Given a family of algebras indexed by I and an ultrafilter U on I, the ultraproduct is the direct product modulo the congruence identifying elements that agree on a set in U.
Over a principal ultrafilter the construction collapses to a single factor and gives nothing. Over a free ultrafilter it produces genuinely new algebras, and it is the mechanism behind compactness, non-standard models and — here — Jónsson's lemma. The detailed model theory, including Łoś's theorem, belongs to the Model-Theoretic stream.
02The statement
If V(K) is congruence-distributive, then every subdirectly irreducible algebra in V(K) belongs to HS(PU(K)) — the homomorphic images of subalgebras of ultraproducts of members of K.
The gain comes from two places at once. Ultraproducts are much more restrictive than arbitrary products, and the reordering puts the product operator innermost, so no products of large families are formed after taking subalgebras and quotients.
03Why distributivity is essential
The proof works by analysing a congruence on a subdirect product using the distributive law in the congruence lattice.
- Set upA subdirectly irreducible A ∈ V(K) is a quotient of a subalgebra of a product of members of K. Let the projection kernels be θ_i.
- The monolith forces concentrationBecause A is subdirectly irreducible its monolith is the least non-trivial congruence. Pulling back, the corresponding congruence must not be split across the factors.
- Distributivity does the splittingIn a distributive congruence lattice, a congruence meeting a finite join must meet one of the joinands. Iterating gives a family of indices that is closed under supersets and finite intersections — a filter.
- The filter is an ultrafilterMaximality of the analysis forces the filter to be an ultrafilter, and the corresponding quotient is an ultraproduct.
For congruence-modular but not distributive varieties there is no analogue. Groups form a congruence-permutable, hence modular, variety, and the subdirectly irreducible groups in a variety generated by a finite group are not confined to HS of ultraproducts of it. Any attempt to apply the lemma outside the distributive setting is simply invalid.
04The finite case
- input: finite set K of finite algebras, V(K) congruence-distributive
- an ultraproduct of a FINITE family of FINITE algebras is isomorphic to a factor
- (the ultrafilter is principal on a finite index set, or concentrates)
- more precisely: P_U(K) ⊆ I(K) when K is a finite set of finite algebras
- Jónsson's lemma then gives: SI members of V(K) ⊆ HS(K)
- HS(K) is a finite, explicitly computable set of finite algebras
- bound: every SI member has at most max{ |A| : A ∈ K } elements
A finite bound on the subdirectly irreducibles is an extremely strong conclusion. It makes the variety residually finite with an explicit bound, and it is the hypothesis Baker's finite basis theorem needs.
05Consequences
06Scope and limits
| Variety | CD? | Lemma applies? |
|---|---|---|
| Lattices and expansions | Yes | Yes |
| Boolean algebras | Yes | Yes, trivially — one SI |
| Heyting algebras | Yes | Yes |
| Discriminator varieties | Yes | Yes, and sharply |
| Groups | No | No — modular but not distributive |
| Rings | No | No |
| Modules | No | No |
| Quasigroups | No | No |
| Semigroups | No | No |
The division is stark: the algebras of logic are congruence-distributive and the algebras of classical algebra are not. This is the single largest reason the structure theory of Chapter IV concerns lattice-like varieties rather than group-like ones, and why the commutator theory had to be developed separately for the modular case.
Frequently asked
Does Jónsson's lemma need the axiom of choice?
It needs ultrafilters, hence BPI. For finitely generated varieties over finite algebras the ultraproducts collapse and no choice is required, which is why the finite case is the one used computationally.
Is the converse of Jónsson's lemma true?
No. Containment of the subdirectly irreducibles in HS(P_U(K)) does not force congruence distributivity. The lemma is a one-way implication, and distributivity is a hypothesis rather than a characterisation.
What replaces Jónsson's lemma for modular varieties?
Nothing as sharp. The commutator theory of Smith, Hagemann–Herrmann and Freese–McKenzie provides tools for congruence-modular varieties, and finite basis results were later obtained in that setting, but there is no statement locating the subdirectly irreducibles as tightly. The gap between the modular and distributive cases is real.
- S. Burris and H. P. Sankappanavar, A Course in Universal Algebra, Millennium Edition (a corrected re-typesetting of Springer GTM 78, 1981).
- G. Grätzer, Universal Algebra, 2nd edition, Springer.
- R. McKenzie, G. McNulty and W. Taylor, Algebras, Lattices, Varieties, Volume I.
Original KEVOS® explanatory article. Written from the topic map of the cited works; no text is reproduced from them.
