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GuidePublished 15 Aug 20265 min readBy Kevin Joginsimultaneous equationssystems of equationssubstitutionelimination
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KEVOS AISystems of Linear Equations: Substitution and Elimination

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Systems of Equations

Systems of Linear Equations: Substitution and Elimination

Two equations in two unknowns, the two elementary methods, and the geometric meaning of a solution as an intersection.

Category Engineering / MathematicsStream Systems of EquationsLevel CoreReading 5 minSource Week 10, pages 7-10; supplementary notes

What this page covers

  • Recognise a system as linear
  • Solve by substitution
  • Solve by elimination
  • Interpret the solution as the intersection of two lines
On this page
  1. What a system is
  2. Substitution
  3. Elimination
  4. Which method to choose
  5. The geometric picture
  6. Common mistakes
  7. Frequently asked questions

What a system is

A system is several equations that must hold at the same time. A solution is a set of values satisfying every one of them, not just some.

Linear system

Every variable appears only to the first power. The source gives the test negatively: linear because there are no x2, xy, y2 or √x terms.

Standard form

Unknowns on the left, constants on the right, like terms aligned in columns.

Rearranging — the source's example

2x + 3y = -x + y + 53x + y - 4 = x - yAs given
3x + 2y = 52x + 2y = 4Source, Week 10, page 8. Standard form

The rearrangement is not cosmetic. Elimination depends on like terms sitting in the same column, and the augmented-matrix methods of Week 11 depend on it absolutely.

Substitution

  1. Solve one equation for one variable, choosing whichever is easiest to isolate.
  2. Substitute that expression into the other equation, which then has only one unknown.
  3. Solve the resulting single equation.
  4. Back-substitute to find the other variable.
  5. Check in both original equations.

Worked example — the source's case

Solve 2x + 3y = 2 and 4x - y = 1.

From (2): y = 4x - 1Substituting in (1): 2x + 3(4x - 1) = 22x + 12x - 3 = 214x = 5x = 514Source example, Week 10, page 7
y = 4(514) - 1 = 2014 - 1414 = 37Back-substituting
Check

In (1): 1014 + 97 = 57 + 97 = 2 ✓. In (2): 2014 - 37 = 107 - 37 = 1 ✓.

A cleaner case — the source's second

Solve 3x + 2y = 5 and x + y = 2.

From (2): y = 2 - x3x + 2(2 - x) = 53x + 4 - 2x = 5x = 1y = 2 - 1 = 1Source, Week 10, page 8. Solution (1, 1)

The source draws the two lines meeting at (1, 1), which is what the solution means geometrically.

Note

Substitution also handles non-linear systems. The source solves y2 + x = 0 with 2x + 3y = -2 by isolating x = -1 - 32y and substituting, giving 2y2 - 3y - 2 = 0, hence y = 2 or y = -12. Two solutions, because a line can cut a parabola twice.

Elimination

Multiply the equations so that one variable has matching coefficients, then add or subtract to remove it.

  1. Choose a variable to eliminate.
  2. Multiply each equation by whatever makes that variable's coefficients equal in size.
  3. Add or subtract to eliminate it.
  4. Solve for the remaining variable.
  5. Back-substitute and check.

Worked example — the source's case

Solve 3x + 2y = 5 and x + y = 2.

Multiply (2) by 3: 3x + 3y = 6Subtract (1): (3x + 3y) - (3x + 2y) = 6 - 5y = 1x = 2 - 1 = 1Source example, Week 10, page 9. Same answer as substitution
Watch out

Subtract every term, including the constants. Writing the second equation with all its signs reversed on a separate line before adding is slower and far safer than subtracting mentally.

A case needing both equations multiplied

Solve 2x - 3y = 4 and 3x + 2y = 19.

Multiply (1) by 3 and (2) by 2:6x - 9y = 126x + 4y = 38Subtract: -13y = -26y = 2Source example, Week 10, pages 9-10
6x - 9(2) = 126x = 30x = 5Back-substituting
The source's own check

In the second original equation: 3(5) + 2(2) = 15 + 4 = 19 ✓. Checking in the equation not used for back-substitution is the meaningful test.

Which method to choose

Choosing between them
SituationBetter methodWhy
A variable has coefficient 1SubstitutionIsolating it introduces no fractions
All coefficients awkwardEliminationMultiplying is easier than dividing
The system is non-linearSubstitutionElimination assumes linearity
Three or more equationsEliminationIt generalises to Gaussian elimination
The system will be solved by computerEliminationIt is the basis of the matrix algorithms

Elimination is the more important of the two in the long run. Everything in Week 11 — augmented matrices, row operations, row-echelon form — is elimination made systematic.

The geometric picture

Each linear equation in two unknowns is a line. Solving the system means finding where the lines meet.

Three possibilities
LinesSolutionsName
Cross at one pointExactly oneConsistent, independent
Parallel and distinctNoneInconsistent
IdenticalInfinitely manyDependent

The source draws all three cases. Two distinct lines in a plane either meet once or not at all; there is no way for them to meet exactly twice. The three cases are developed in Consistent, Inconsistent and Dependent Systems.

Common mistakes

Errors and checks
MistakeCorrectCheck
Not rearranging to standard formAlign like terms firstElimination depends on the alignment
Subtracting only some termsEvery term, both sidesWrite the negated equation on its own line
Multiplying only one side of an equationMultiply bothOtherwise the equation changes
Checking in one equation onlyCheck in bothOne equation passes for many wrong pairs
Substituting back into the rearranged equationUse an originalAn early error would be reproduced
Stopping after finding one variableFind bothA solution is an ordered pair

Frequently asked questions

Which method is better?

Substitution when one variable already has a coefficient of 1. Elimination when the coefficients are awkward, or when there are three or more equations — it is what Gaussian elimination generalises.

Why put the system in standard form first?

Because elimination lines up like terms in columns, and the constants must be on the right. The source rearranges every system before solving.

What does the solution mean geometrically?

The point where the two lines cross. The source draws the graphs alongside the algebra for exactly this reason.

Do systems have to be linear?

No, but non-linear systems need more care. The source works y2 + x = 0 with 2x + 3y = -2 by substitution, which produces a quadratic in y and two solutions.

Related pages

  • Consistent, Inconsistent and Dependent Systems
  • Systems in Three Variables
  • Gaussian Elimination and Row-Echelon Form
  • The Four Forms of a Straight Line

Source. Handwritten teaching notes, Week 10, pages 7-10, with the typed supplementary notes on simultaneous equations.

This page is an original exposition prepared for the KEVOS® knowledge library. It restates, reorganises and verifies the mathematics of the supplied teaching notes; it is not a reproduction of them. Numerical values taken from the notes are identified as source examples and are not presented as engineering standards.

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NEXT LESSON →Consistent, Inconsistent and Dependent SystemsGuide · Engineering MathematicsSystems in Three VariablesGuide · Engineering MathematicsSolving Systems by Elimination and SubstitutionGuide · Engineering MathematicsGauss-Jordan ReductionGuide · Engineering Mathematics
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