Executive Summary
Wedderburn–Artin says a simple artinian ring is for a division ring . This page proves the exact analogue one level up: a semiperfect ring whose radical quotient is simple is for a local ring , with and determined. Passing from a division ring to a local ring is precisely the price of allowing a radical.
The commutative case is even cleaner: a commutative ring is semiperfect if and only if it is a finite direct product of local rings. Combined with the Hopkins–Levitzki theorem this yields the classical Akizuki–Cohen characterisation — a commutative ring is artinian iff it is noetherian of Krull dimension zero.
Overview
For a general semiperfect ring , the quotient is a finite product of simple artinian rings. Two special cases admit a complete structure theory.
The first case, , applies when has a single Wedderburn factor. Equivalently, all the principal indecomposables of are isomorphic to one another, so is a matrix ring over the endomorphism ring of any one of them.
The second case is commutativity. Here every idempotent is central, so the decomposition of into orthogonal local idempotents is at once a decomposition of the ring into a product of local rings — that is .
should be read as the semiperfect extension of Wedderburn–Artin. Both statements say one simple factor means one matrix ring; the difference is that the coefficient ring is a division ring in the semisimple case and merely local in the semiperfect one.
Learning Objectives
- Prove that with local is semiperfect with simple radical quotient and is indecomposable as a ring.
- Prove the converse, constructing as the endomorphism ring of a principal indecomposable.
- State the uniqueness of and of and justify it by Krull–Schmidt.
- Prove that commutative semiperfect rings are exactly finite products of local rings.
- Derive the Akizuki–Cohen equivalences for commutative artinian rings.
- Give an indecomposable semiperfect ring whose radical quotient is decomposable.
Definitions
- simple
- has no proper nonzero two-sided ideals. Together with semiperfectness this forces to be simple artinian, i.e. for a division ring .
- Local ring
- is a division ring; equivalently the non-units of form an ideal.
- Ring decomposition
- with nonzero; equivalent to the existence of a central idempotent other than and .
- Krull dimension zero
- For a commutative ring, every prime ideal is maximal. Equivalently, the ring has no strict inclusions between primes.
- Artinian local ring
- A local ring satisfying the descending chain condition; its maximal ideal is nilpotent and it has finite length over itself.
In , artinian and noetherian are unambiguous because the ring is commutative; elsewhere on this page the semiperfect hypothesis is side-neutral by definition.
Key Results
For a ring the following are equivalent:
- is semiperfect and is a simple ring;
- for some and some local ring .
When these hold, is uniquely determined and is unique up to isomorphism. Moreover is indecomposable as a ring.
**(2) (1).** Let be local with . Then is semiperfect by , and is simple artinian, hence simple.
**(1) (2).** By write with the mutually orthogonal local idempotents, so that and with each a minimal right ideal. Since is simple artinian it has a unique simple right module up to isomorphism, so all the are isomorphic. Isomorphism of idempotent-generated right ideals is detected modulo the radical — if and only if — so all the are isomorphic. Writing we get and hence
and is local because is a local idempotent.
Uniqueness. Suppose with local. Then is a direct sum of copies of the column module , each with local endomorphism ring . By the Krull–Schmidt–Azumaya theorem such a decomposition of is unique up to isomorphism and permutation, so is the number of indecomposable summands of and is determined up to isomorphism.
Indecomposability. The centre of consists of the scalar matrices with . A central idempotent of therefore has the form with ; a local ring has no idempotents besides and , so and has only the trivial central idempotents. Hence is indecomposable as a ring.
If is semiperfect but has several Wedderburn factors, , one would like to lift the corresponding centrally primitive idempotents of to central idempotents of and split accordingly. This fails: guarantees lifting of idempotents, not of central idempotents. The upper triangular ring is indecomposable with .
A commutative ring is semiperfect if and only if is a finite direct product of (commutative) local rings.
() Every local ring is semiperfect, and a finite direct product of semiperfect rings is semiperfect by .
() Let be commutative and semiperfect, and take with the orthogonal local idempotents, as in . In a commutative ring every element is central, so each is a central idempotent and the decomposition of the module is a decomposition of the ring:
Each factor is local because is a local idempotent.
Hence is a finite product of local rings. Note the number of factors and the factors themselves are then determined: the are the centrally primitive idempotents of , which in the commutative case are canonical.
For a commutative ring the following are equivalent:
- is artinian;
- is a finite direct product of artinian local rings;
- is noetherian and has Krull dimension , i.e. every prime ideal of is maximal.
**(1) (2).** An artinian commutative ring is semiperfect, so presents it as a finite product of local rings, and each factor — a quotient of — is artinian. Conversely a finite product of artinian rings is artinian.
**(1) (3).** Noetherianness is the Hopkins–Levitzki theorem. For dimension zero, let be prime; then is an artinian integral domain. For the chain stabilises, so for some , and cancelling in the domain gives . So is a field and is maximal.
**(3) (1).** Assume is noetherian of dimension . In a noetherian ring every ideal contains a finite product of prime ideals; applied to the zero ideal this gives primes — hence, by dimension , maximal ideals — with . Consider the filtration
Each successive quotient is annihilated by , hence is a vector space over the field , and it is finitely generated because is noetherian. A finite-dimensional vector space has a composition series, so itself has finite length as an -module and is therefore artinian.
The equivalence (1) (3) survives without commutativity in the following form: a ring is right artinian if and only if is right noetherian and is simple artinian for every prime ideal . The proof follows the commutative one, with simple artinian replacing field.
Proof Techniques and Method
How these proofs work, and which move is reusable.
Count isomorphism classes downstairs
A simple quotient means one simple module, hence all principal indecomposables are isomorphic upstairs. Recognising a ring as is always a statement about how many isomorphism classes of summands has.
Detect isomorphism modulo the radical
For idempotents : iff . This is what transports the semisimple computation back to , and it is used in almost every semiperfect structure proof.
Use commutativity to centralise
Once idempotents are central, a module decomposition is a ring decomposition. Everything special about the commutative case comes from this single observation.
The Akizuki–Cohen proof adds a fourth, purely commutative technique: build a filtration by products of maximal ideals and read off finite length one layer at a time. The same argument shows that a noetherian ring in which some product of maximal ideals vanishes is artinian, which is the form usually needed in practice.
Worked Example
A matrix ring over a local ring
Take and . Then and , which is simple. By the pair is determined by : any isomorphism with local forces and .
Indecomposability is visible: , and has no idempotents besides and , so is not a product of two nonzero rings — even though is far from being a domain.
The commutative case:
is commutative artinian, hence semiperfect. Its maximal ideals are and , so and . The idempotents of do lift here, to and :
An orthogonal pair of idempotents summing to — exactly the decomposition promised by and .
Hence , a product of two artinian local rings, illustrating and clause (2) of .
Indecomposable with a decomposable quotient
Let be a field and , the upper triangular matrices. Then is the strictly upper triangular part and , which is not simple, so does not apply. And indeed:
The central idempotent of lifts to , which is idempotent but not central.
So is an indecomposable semiperfect ring whose radical quotient decomposes. This is the precise obstruction referred to in the Remark above, and it is why block theory is a separate development rather than a corollary.
Comparison and Classification
| Extra hypothesis | Structure of | Reference | |
|---|---|---|---|
| , a division ring | none | is local | definition |
| , simple | none | , local, indecomposable | (23.10) |
| , product of fields | commutative | , each local | (23.11) |
| none | no product decomposition in general | Remark, | |
| central idempotents lift | with each simple | block theory, §25 |
| Noetherian | Dimension | Artinian | Semiperfect | |
|---|---|---|---|---|
| yes | yes | yes | yes | |
| a field | yes | yes | yes | yes |
| yes | yes | yes | yes | |
| yes | no | no | no | |
| yes | no | no | yes | |
| localised away from | yes | no | no | no |
| no | yes | no | yes |
Commutative rings against the three Akizuki–Cohen conditions
The two yes entries in the last column with no in the artinian column show how much wider semiperfect is than artinian even among commutative rings: is local, and the last ring is local with a square-zero maximal ideal.
Relationship Map
- Semiperfect ring
- simple
- , local
- and unique
- indecomposable as a ring
- commutative
- , each local
- the are the centrally primitive idempotents
- artinian iff every is artinian
- general case
- is a finite product of simple artinian rings
- central idempotents may fail to lift
- block decomposition treated separately
- simple
The first arrow is strict — is semiperfect and not artinian — and so is the second, since a semilocal domain with two maximal ideals is not semiperfect. See Semiperfect Rings: Definition and First Examples for that witness.
Your semiperfect ring : what structure can you claim?
Applications and Industry Use
Applications here means where this structure is used — inside mathematics and in the engineering and computing disciplines that consume it.
Zero-dimensional rings
is the standard reason that an artinian ring is a finite product of local rings, which underlies primary decomposition, the structure of fibres of finite morphisms, and the definition of intersection multiplicity.
Reduction of orders
For a maximal order in a division algebra over a -adic field, the completion is with local; pins down and from the residue data and is the local input to classification by Hasse invariants.
Codes over finite chain rings
A finite commutative ring is artinian, hence by a product of local rings; code constructions therefore reduce, coordinate by coordinate, to the local case with its residue field.
Splitting a finite ring
Systems compute the idempotent decomposition of a finite commutative ring to reduce arithmetic to local factors — the same Chinese-Remainder step that formalises for arbitrary commutative semiperfect rings.
Honest summary: and are recognition theorems. Their value is that they turn a hypothesis you can check into an isomorphism you can compute with.
Failure Modes and Common Mistakes
- needs finite: an infinite product of fields is commutative, has all idempotents you could want, and is not semiperfect because it is not semilocal.
- The local ring in is not a subring of in any canonical way — it is for a choice of , determined only up to isomorphism.
- Do not read as saying every indecomposable semiperfect ring is a matrix ring over a local ring. is indecomposable and is not of that form.
- In , *Krull dimension * means every prime is maximal, not that the ring has a unique prime. A product of fields has primes and dimension .
Historical Notes and Lessons Learned
- 1908WedderburnStructure theorem for finite-dimensional algebras: a simple algebra is a matrix algebra over a division algebra. This is the shape reproduces one level up.
- 1927ArtinExtension of the structure theory to rings with the descending chain condition, making simple artinian the right hypothesis rather than finite-dimensional.
- 1935AkizukiCommutative rings that are noetherian of dimension zero are shown to be artinian, the implication that is hardest in .
- 1939Hopkins and LevitzkiA one-sided artinian ring with identity is one-sided noetherian, supplying the reverse implication in the noncommutative setting.
- 1940sCohenCohen's work on the ideal theory of local rings puts the zero-dimensional characterisation into its standard commutative-algebra form.
- 1960BassSemiperfect rings are introduced, and results such as are recognised as the natural extension of Wedderburn–Artin beyond the semisimple case.
The lesson is that each generalisation replaced a hypothesis about the ring by a hypothesis about its radical quotient plus a lifting property. Once that is the frame, is forced: a single simple factor downstairs can only come from a matrix ring over something with a unique maximal one-sided ideal.
Quick Reference
| Reference | Statement | Hypotheses |
|---|---|---|
| (23.10) | with local; , unique; indecomposable | semiperfect and simple |
| (23.11) | is a finite product of local rings | commutative and semiperfect |
| (23.12) | Artinian product of artinian local rings noetherian of dimension | commutative |
| Remark | Right artinian right noetherian with all simple artinian | ranges over prime ideals |
Frequently Asked Questions
Why does produce a local ring rather than a division ring?
Because the radical is no longer zero. In Wedderburn–Artin the ring equals its own semisimple quotient and the coefficient ring is of a simple module, a division ring. Here the coefficient ring is of a principal indecomposable, whose endomorphism ring is local rather than a division ring — exactly the corner .
Is in canonically attached to ?
Up to isomorphism, yes; canonically as a subring, no. depends on the choice of , and different choices are conjugate by a unit. What is intrinsic is the isomorphism class, pinned down by Krull–Schmidt applied to .
Why can't be extended to arbitrary semiperfect rings?
Because the product decomposition of is carried by central idempotents, and semiperfectness only guarantees that idempotents lift. has yet is indecomposable, since its centre is just the scalars. Recovering a product decomposition requires the block theory of §25.
Does say a commutative semiperfect ring is artinian?
No. It says it is a finite product of local rings, and local rings need not be artinian: and are local, semiperfect and not artinian. Artinianness is the extra condition in .
Where is commutativity actually used in ?
In exactly one place: it makes the local idempotents central, so that the module decomposition is a ring decomposition. Without it, is only a right ideal and there is no product.
How is Akizuki–Cohen related to the Hopkins–Levitzki theorem?
Hopkins–Levitzki supplies the implication artinian noetherian in general, and the commutative case was obtained earlier by Akizuki. The hard direction of is the converse, noetherian plus dimension zero artinian, proved by the filtration by products of maximal ideals.
References
- T. Y. Lam, A First Course in Noncommutative Rings, Graduate Texts in Mathematics 131, Springer-Verlag, 1991, §23, results (23.10)–(23.12).
- M. F. Atiyah and I. G. Macdonald, Introduction to Commutative Algebra, Addison-Wesley, 1969, chapter on artinian rings.
- H. Bass, “Finitistic dimension and a homological generalization of semi-primary rings”, Transactions of the American Mathematical Society 95 (1960), 466–488.
- N. Jacobson, Structure of Rings, American Mathematical Society Colloquium Publications 37, revised edition, 1964, chapters on the structure of rings with radical.
- C. W. Curtis and I. Reiner, Methods of Representation Theory, Volume I, Wiley, 1981, chapters on local rings, orders and blocks.
AI Suggested Questions
- Prove that for idempotents if and only if the images are isomorphic modulo the radical.
- Give an indecomposable semiperfect ring, other than a triangular matrix ring, whose radical quotient is not simple.
- For which local rings is left noetherian but not left artinian?
- How are the blocks of a semiperfect ring defined, and when do they correspond to the Wedderburn factors of the radical quotient?
- Prove that in a noetherian commutative ring every ideal contains a finite product of prime ideals.
- State and prove the noncommutative analogue of Akizuki–Cohen mentioned in the remark.
- Classify the commutative semiperfect rings of finite cardinality.
